2x^2-6272=0

Solution for 2x^2-6272=0 equation:

2x^2-6272=0

a = 2; b = 0; c = -6272;
Δ = b2-4ac
Δ = 02-4·2·(-6272)
Δ = 50176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{50176}=224$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-224}{2*2}=\frac{-224}{4}
=-56
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+224}{2*2}=\frac{224}{4}
=56
$